Поиск не индексированных внешних ключей в Oracle

  
  select table_name, constraint_name,
        cname1 || nvl2(cname2,','||cname2,null) ||
        nvl2(cname3,','||cname3,null) || nvl2(cname4,','||cname4,null) ||
        nvl2(cname5,','||cname5,null) || nvl2(cname6,','||cname6,null) ||
        nvl2(cname7,','||cname7,null) || nvl2(cname8,','||cname8,null)
               columns
     from ( select b.table_name,
                   b.constraint_name,
                   max(decode( position, 1, column_name, null )) cname1,
                   max(decode( position, 2, column_name, null )) cname2,
                   max(decode( position, 3, column_name, null )) cname3,
                   max(decode( position, 4, column_name, null )) cname4,
                   max(decode( position, 5, column_name, null )) cname5,
                   max(decode( position, 6, column_name, null )) cname6,
                   max(decode( position, 7, column_name, null )) cname7,
                   max(decode( position, 8, column_name, null )) cname8,
                   count(*) col_cnt
              from (select substr(table_name,1,30) table_name,
                           substr(constraint_name,1,30) constraint_name,
                           substr(column_name,1,30) column_name,
                           position
                      from user_cons_columns ) a,
                   user_constraints b
             where a.constraint_name = b.constraint_name
               and b.constraint_type = 'R'
             group by b.table_name, b.constraint_name
          ) cons
    where col_cnt > ALL
            ( select count(*)
                from user_ind_columns i
               where i.table_name = cons.table_name
                 and i.column_name in (cname1, cname2, cname3, cname4,
                                       cname5, cname6, cname7, cname8 )
                 and i.column_position <= cons.col_cnt
               group by i.index_name
            )